Golf Balls By Distance

The path of a golf ball hit with a 9iron can be modeled with the quadratic equation y =- 0.042x ^ 2 +5 x?

where x is the distance in meters from the point he was shot and y is the height of the golf ball at the feet Suppose the earth is flat. A. Find the maximum height reached by the bullet and B. How far from where he was hitting the ball touches the ground?

A. The ball reaches maximum height when the derivative of the function is zero. y '= – 5 + 0 = 0.084x – 0.084x + 5 (- 5 / – 0.084) = xx ≈ 59.5 meters. The height of 59.5 m is y = – 0,042 * (59.5) ^ 2 * 5 (59.5) 148.8 m ≈ ———————— — ——- B The ball flight is parabolic, so that one can sense that the ball hit the ground 2 * 59.5 = 119 meters. Algebra, find the zeros y = – 0.042x ^ 2 + y = 5x – 0.042x ^ 2 + y = 5x x * (-0.042x + 5), if a zero at x = 0, the other is zero 0 = (-0.042x + 5) = 5 x = 0.042x (5 / 0.042) ≈ 119 yards.